use the magnitudes (richter scale) of the earthquakes listed in the data set below. find the mean and data…

use the magnitudes (richter scale) of the earthquakes listed in the data set below. find the mean and data set. is the magnitude of an earthquake measuring 7.0 on the richter scale an outlier (data value t away from the others) when considered in the context of the sample data given in this data set? explai\n0.76 2.67 0.47 0.07 1.07 0.26 1.97 0.36 0.67 1.75 \n1.17 0.59 2.06 1.89 1.77 2.97 1.79 1.28 1.77 2.62 \n1.61 1.81 2.55 0.68 2.97 2.38 0.25 2.58 0.24 2.95 \n1.76 1.27 2.91 2.63 1.84 0.45 1.51 0.49 0.11 0.81 \n1.75 0.89 2.79 2.02 0.16 1.13 2.85 0.35 1.07 1.96
Answer
Explanation:
Step1: Calculate the sum of data
Sum all the magnitudes: [0.76 + 2.67+0.47 + 0.07+1.07+0.26+1.97+0.36+0.67+1.75+1.17+0.59+2.06+1.89+1.77+2.97+1.79+1.28+1.77+2.62+1.61+1.81+2.55+0.68+2.97+2.38+0.25+2.58+0.24+2.95+1.76+1.27+2.91+2.63+1.84+0.45+1.51+0.49+0.11+0.81+1.75+0.89+2.79+2.02+0.16+1.13+2.85+0.35+1.07+1.96 = 84.97]
Step2: Calculate the number of data points
Count the number of magnitudes. There are (n = 50) data - points.
Step3: Calculate the mean
The mean (\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}), so (\bar{x}=\frac{84.97}{50}=1.6994)
Step4: Analyze if 7.0 is an outlier
The values in the data - set range from approximately (0.07) to (2.97). A value of (7.0) is much larger than any of the values in the data - set and is far away from the others. So it would be an outlier.
Answer:
The mean is (1.6994). The magnitude of an earthquake measuring (7.0) on the Richter scale is an outlier because it is much larger than all the values in the given data - set.