use the previously determined values $sum(x - \bar{x})(y - \bar{y}) = 1,568.26$ and $sum(x - \bar{x})^2 =…

use the previously determined values $sum(x - \bar{x})(y - \bar{y}) = 1,568.26$ and $sum(x - \bar{x})^2 = 105.8$ to compute $b$, rounding the result to six decimal places.\n$b=\frac{sum(x - \bar{x})(y - \bar{y})}{sum(x - \bar{x})^2}$\n$=\frac{1,568.26}{105.8}$

use the previously determined values $sum(x - \bar{x})(y - \bar{y}) = 1,568.26$ and $sum(x - \bar{x})^2 = 105.8$ to compute $b$, rounding the result to six decimal places.\n$b=\frac{sum(x - \bar{x})(y - \bar{y})}{sum(x - \bar{x})^2}$\n$=\frac{1,568.26}{105.8}$

Answer

Explanation:

Step1: Substitute given values

Given $\sum(x - \bar{x})(y - \bar{y})=1568.26$ and $\sum(x - \bar{x})^2 = 105.8$, substitute into the formula $b=\frac{\sum(x - \bar{x})(y - \bar{y})}{\sum(x - \bar{x})^2}$. $b=\frac{1568.26}{105.8}$

Step2: Calculate the value of b

$b = 14.822873$

Answer:

$14.822873$