use the table below to compute $(x - \\bar{x})^2$, using the previously determined value $\\bar{x}=10.3$.\n|r…

use the table below to compute $(x - \\bar{x})^2$, using the previously determined value $\\bar{x}=10.3$.\n|representative age|$x - \\bar{x}$|$(x - \\bar{x})^2$|\n|----|----|----|\n|4.0|$4.0 - 10.3=-6.3$|$(-6.3)^2 = 39.69$|\n|7.0|$7.0 - 10.3=-3.3$|$(-3.3)^2=square$|\n|10.0|$10.0 - 10.3=-0.3$|$(-0.3)^2=square$|\n|13.5|$13.5 - 10.3 = 3.2$|$(3.2)^2=square$|\n|17.0|$17.0 - 10.3 = 6.7$|$(6.7)^2=square$|\ncalculate the sum $sum(x - \\bar{x})^2$.\n$sum(x - \\bar{x})^2=square$
Answer
Explanation:
Step1: Calculate $(-3.3)^2$
$(-3.3)^2=(-3.3)\times(-3.3) = 10.89$
Step2: Calculate $(-0.3)^2$
$(-0.3)^2=(-0.3)\times(-0.3)=0.09$
Step3: Calculate $(3.2)^2$
$(3.2)^2 = 3.2\times3.2=10.24$
Step4: Calculate $(6.7)^2$
$(6.7)^2=6.7\times6.7 = 44.89$
Step5: Calculate the sum $\sum(x - \bar{x})^2$
$\sum(x - \bar{x})^2=39.69+10.89 + 0.09+10.24+44.89=105.8$
Answer:
For $(-3.3)^2$: $10.89$ For $(-0.3)^2$: $0.09$ For $(3.2)^2$: $10.24$ For $(6.7)^2$: $44.89$ For $\sum(x - \bar{x})^2$: $105.8$