valentina has 3 raffle tickets. one hundred tickets were sold. her name was not drawn for the first prize…

valentina has 3 raffle tickets. one hundred tickets were sold. her name was not drawn for the first prize. what is the probability that her name will be drawn for the second prize? (leave answer in fraction form in lowest terms, and remember that the first ticket was already drawn out and was not replaced)

valentina has 3 raffle tickets. one hundred tickets were sold. her name was not drawn for the first prize. what is the probability that her name will be drawn for the second prize? (leave answer in fraction form in lowest terms, and remember that the first ticket was already drawn out and was not replaced)

Answer

Explanation:

Step1: Determine remaining tickets

Since 1 ticket is already drawn out of 100, there are 99 remaining tickets.

Step2: Calculate probability

Valentina has 3 tickets. Probability = $\frac{\text{Number of Valentina's tickets}}{\text{Number of remaining tickets}}=\frac{3}{99}$.

Step3: Simplify fraction

$\frac{3}{99}=\frac{3\div3}{99\div3}=\frac{1}{33}$.

Answer:

D. 1/33