which z - values correspond to the outside 60% of the standard normal distribution? round your answers to…

Answer:

$z < - 0.842$ or $0.842 < z$

Explanation:

Step1: Calculate middle area

The outside area is 60%, so the middle area is $1 - 0.6=0.4$.

Step2: Calculate area on one - side of the middle

The area on one - side of the middle is $\frac{0.4}{2}=0.2$.

Step3: Find the cumulative probability

The cumulative probability from the left - hand side up to the left - hand boundary of the middle region is $0.5 - 0.2 = 0.3$.

Step4: Look up z - value in z - table

Looking up the value 0.3 in the standard normal (z -) table, we find the z - value corresponding to a cumulative probability of 0.3 is approximately $z=-0.842$. Due to the symmetry of the standard normal distribution, the z - value on the right - hand side is $z = 0.842$.