if y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8?\n$\frac{1}{9}$\n$\fra…

Explanation:

Step1: Define direct variation

Direct variation means $y = kx$, where $k$ is the constant of proportionality.

Step2: Solve for constant $k$

Substitute $y=6$, $x=72$: $6 = k \times 72$ $k = \frac{6}{72} = \frac{1}{12}$

Step3: Find $y$ when $x=8$

Use $y = \frac{1}{12}x$, substitute $x=8$: $y = \frac{1}{12} \times 8 = \frac{8}{12} = \frac{2}{3}$

Answer:

$\boldsymbol{\frac{2}{3}}$ (Option: $\boldsymbol{\frac{2}{3}}$)