the weights of the chocolate in hershey kisses are normally distributed with a mean of 4.5338 g and a…

the weights of the chocolate in hershey kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.1039 g.\na. for the bell - shaped graph of the normal distribution of weights of hershey kisses, what is the area under the curve?\nb. what is the value of the median?\nc. what is the value of the mode?\nd. what is the value of the variance?\na. for the bell - shaped graph of the normal distribution of weights of hershey kisses, what is the area under the curve?\n(type an integer or a decimal. do not round.)

the weights of the chocolate in hershey kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.1039 g.\na. for the bell - shaped graph of the normal distribution of weights of hershey kisses, what is the area under the curve?\nb. what is the value of the median?\nc. what is the value of the mode?\nd. what is the value of the variance?\na. for the bell - shaped graph of the normal distribution of weights of hershey kisses, what is the area under the curve?\n(type an integer or a decimal. do not round.)

Answer

Explanation:

Step1: Recall property of normal - distribution area

The total area under the curve of a normal distribution is always 1. 1

Step2: Recall median property of normal - distribution

In a normal distribution, the mean, median, and mode are equal. Given mean $\mu = 4.5338$ g, so median = 4.5338 g. 4.5338

Step3: Recall mode property of normal - distribution

In a normal distribution, the mean, median, and mode are equal. Given mean $\mu = 4.5338$ g, so mode = 4.5338 g. 4.5338

Step4: Recall variance - standard - deviation relationship

The variance $\sigma^{2}$ is the square of the standard deviation $\sigma$. Given $\sigma=0.1039$ g, then $\sigma^{2}=(0.1039)^{2}=0.01079521$ g². 0.01079521

Answer:

a. 1 b. 4.5338 c. 4.5338 d. 0.01079521