the weights, in pounds, of mike’s five pet dogs are listed below. what is the mean absolute deviation (mad)…
the weights, in pounds, of mike’s five pet dogs are listed below. what is the mean absolute deviation (mad) of the weights? 16, 23, 27, 41, 53 type the answer in the box. pounds
Answer
Explanation:
Step1: Calculate the mean
The mean $\bar{x}=\frac{16 + 23+27+41+53}{5}=\frac{160}{5}=32$.
Step2: Calculate the absolute - deviations
$|16 - 32|=16$, $|23 - 32| = 9$, $|27 - 32|=5$, $|41 - 32| = 9$, $|53 - 32|=21$.
Step3: Calculate the mean of the absolute - deviations
$MAD=\frac{16+9+5+9+21}{5}=\frac{60}{5}=12$.
Answer:
12