you pick a card at random, put it back, and then pick another card at random. what is the probability of…

Explanation:

Step1: Find probability of picking number less than 6

There are 2 numbers (4, 5) less than 6 out of 4 numbers. So probability $P_1=\frac{2}{4}=\frac{1}{2}$.

Step2: Find probability of picking 7

There is 1 number 7 out of 4 numbers. So probability $P_2 = \frac{1}{4}$.

Step3: Use multiplication - rule for independent events

Since the two picks are independent events, the probability of both events occurring is $P = P_1\times P_2$. Substitute $P_1=\frac{1}{2}$ and $P_2=\frac{1}{4}$ into the formula, we get $P=\frac{1}{2}\times\frac{1}{4}=\frac{1}{8}$.

Step4: Convert to percentage

To convert $\frac{1}{8}$ to a percentage, we calculate $\frac{1}{8}\times100% = 12.5%$.

Answer:

12.5%