you pick a card at random. without putting the first card back, you pick a second card at random. what is…

Explanation:

Step1: Calculate probability of first - pick

There are 3 odd numbers (1, 3, 5) out of 6 numbers. So the probability of picking an odd number first, $P_1=\frac{3}{6}$.

Step2: Calculate probability of second - pick

After picking an odd number first (without replacement), there are 5 numbers left and 3 even numbers (2, 4, 6). So the probability of picking an even number second, $P_2 = \frac{3}{5}$.

Step3: Calculate combined probability

Since these are independent - like (in the sense of sequential) events, the probability of both events occurring is the product of their probabilities. $P=P_1\times P_2=\frac{3}{6}\times\frac{3}{5}=\frac{9}{30}=\frac{3}{10}$.

Step4: Convert to percentage

To convert $\frac{3}{10}$ to a percentage, we multiply by 100. $P = \frac{3}{10}\times100%=30%$.

Answer:

30%