you pick a card at random. without putting the first card back, you pick a second card at random.\nwhat is…
you pick a card at random. without putting the first card back, you pick a second card at random.\nwhat is the probability of picking an odd number and then picking an odd number?\nsimplify your answer and write it as a fraction or whole number.
Answer
Explanation:
Step1: Calculate first - pick probability
There are 3 cards (6, 7, 8), and 1 odd - numbered card (7). The probability of picking an odd - numbered card on the first pick is $\frac{1}{3}$.
Step2: Calculate second - pick probability
Since we do not put the first card back, there are 2 cards left. After picking an odd - numbered card (7) on the first pick, there are 0 odd - numbered cards left. So the probability of picking an odd - numbered card on the second pick given that an odd - numbered card was picked on the first pick is $\frac{0}{2}=0$.
Step3: Calculate joint probability
The probability of two dependent events A and B is $P(A\cap B)=P(A)\times P(B|A)$. Here, $P(A)=\frac{1}{3}$ and $P(B|A) = 0$. So $P=\frac{1}{3}\times0 = 0$.
Answer:
0