you pick a card at random. without putting the first card back, you pick a second card at random. what is…
you pick a card at random. without putting the first card back, you pick a second card at random. what is the probability of picking a 6 and then picking a 6? write your answer as a fraction or whole number.
Answer
Explanation:
Step1: Calculate first - pick probability
There is 1 card with number 6 out of 3 cards. So the probability of picking a 6 on the first pick is $P_1=\frac{1}{3}$.
Step2: Calculate second - pick probability
Since the first card is not replaced, there are 2 cards left and 0 cards with number 6 if the first - picked card was 6. So the probability of picking a 6 on the second pick given that a 6 was picked on the first pick is $P_2 = 0$.
Step3: Calculate combined probability
For independent - like (in the sense of sequential non - replacement) events, the probability of both events occurring is the product of their probabilities. So $P = P_1\times P_2=\frac{1}{3}\times0 = 0$.
Answer:
0