you pick a card at random. without putting the first card back, you pick a second card at random. what is…

you pick a card at random. without putting the first card back, you pick a second card at random. what is the probability of picking a 6 and then picking a 3? write your answer as a fraction or whole number.

you pick a card at random. without putting the first card back, you pick a second card at random. what is the probability of picking a 6 and then picking a 3? write your answer as a fraction or whole number.

Answer

Explanation:

Step1: Calculate first - pick probability

The probability of picking a 6 on the first pick is $\frac{1}{4}$ since there is 1 card with a 6 out of 4 total cards.

Step2: Calculate second - pick probability

After picking a 6 on the first pick without replacement, there are 3 cards left. The probability of picking a 3 on the second pick is $\frac{1}{3}$.

Step3: Calculate combined probability

Since these are independent - like events (in the sense of sequential non - replacement picking), we multiply the probabilities of each event. So the probability of picking a 6 and then a 3 is $\frac{1}{4}\times\frac{1}{3}=\frac{1}{12}$.

Answer:

$\frac{1}{12}$