you spin the spinner twice. what is the probability of landing on an even number and then landing on an even…

Explanation:

Step1: Count even - numbered sections

The even - numbered sections on the spinner are 2, 4, 6. So there are 3 even - numbered sections out of 6 total sections. The probability of landing on an even number on the first spin is $P_1=\frac{3}{6}=\frac{1}{2}$.

Step2: Calculate probability of second spin

Since the spins are independent events, the probability of landing on an even number on the second spin is also $P_2 = \frac{3}{6}=\frac{1}{2}$.

Step3: Use multiplication rule for independent events

The probability of both events occurring is $P = P_1\times P_2$. $P=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}$.

Step4: Convert to percentage

To convert $\frac{1}{4}$ to a percentage, we calculate $\frac{1}{4}\times100% = 25%$.

Answer:

25%