you are a sports agents assistant. you are preparing a report on contracts you have obtained for the agents…

you are a sports agents assistant. you are preparing a report on contracts you have obtained for the agents clients. you recently negotiated the following annual contracts: $2.8 million, $18.9 million, $1.5 million, $1.2 million, $1.5 million, and $3.5 million per year. the standard deviation of the data is 6.3, and the range is 17.7. which measure of center is most appropriate, and what is the value of the measure of center? median; $1.35 million mode; $1.5 million median; $2.15 million mean; $4.9 million mean; $5.58 million

you are a sports agents assistant. you are preparing a report on contracts you have obtained for the agents clients. you recently negotiated the following annual contracts: $2.8 million, $18.9 million, $1.5 million, $1.2 million, $1.5 million, and $3.5 million per year. the standard deviation of the data is 6.3, and the range is 17.7. which measure of center is most appropriate, and what is the value of the measure of center? median; $1.35 million mode; $1.5 million median; $2.15 million mean; $4.9 million mean; $5.58 million

Answer

Explanation:

Step1: Arrange data in ascending order

$1.2, 1.5, 1.5, 2.8, 3.5, 18.9$

Step2: Calculate the mean

Mean $=\frac{1.2 + 1.5+1.5 + 2.8+3.5+18.9}{6}=\frac{29.4}{6}=4.9$

Step3: Determine the median

Since there are 6 data - points, the median is the average of the 3rd and 4th ordered values. Median $=\frac{1.5 + 2.8}{2}=2.15$

Step4: Find the mode

The mode is the value that appears most frequently. Mode $ = 1.5$

Step5: Choose the appropriate measure

The data has an out - lier ($18.9$). The median is less affected by outliers than the mean.

Answer:

median; $$2.15$ million