you must type your answers fractions like 2/3 (you do not need to reduce or simplify). help (fractions) the…

you must type your answers fractions like 2/3 (you do not need to reduce or simplify). help (fractions) the table below summarizes the results of a survey that asked about the survey respondents family size (rows) and the number of cars owned (columns). for example, 2 respondents stated that they live by themselves, and own 2 or more cars. the table also gives totals for each category. for example, 23 respondents live by themselves, while 24 respondents own zero cars. suppose a respondent is chosen at random (from out of 89 total). what is the probability that the chosen respondent lives by themselves and owns 2 or more cars? suppose a respondent is chosen at random (from out of 89 total). what is the probability that the chosen respondent lives by themselves or owns 2 or more cars? what is the probability that the chosen respondent lives by themselves? what is the probability that the chosen respondent owns no cars?
Answer
Explanation:
Step1: Recall probability formula
Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$.
Step2: Calculate "lives by themselves or owns 2 or more cars"
Number of people who live by themselves is 23, number of people who own 2 or more cars is 34, and number of people who live by themselves and own 2 or more cars is 2. Using the inclusion - exclusion principle, the number of people who live by themselves or own 2 or more cars is $23 + 34- 2=55$.
Step3: Calculate probability
The total number of respondents is 89. So the probability is $\frac{55}{89}$.
Step4: Calculate probability of owning no cars
The number of people who own no cars is 24. So the probability is $\frac{24}{89}$.
Answer:
The probability that the chosen respondent lives by themselves or owns 2 or more cars is $\frac{55}{89}$. The probability that the chosen respondent owns no cars is $\frac{24}{89}$.